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* OrderedDict  dict subclass that remembers the order entries were added
* defaultdict  dict subclass that calls a factory function to supply missing values
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>>> Point.__doc__                   # docstring for the new class
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>>> p = Point(11, y=22)             # instantiate with positional args or keywords
>>> p[0] + p[1]                     # indexable like a plain tuple
33
>>> x, y = p                        # unpack like a regular tuple
>>> x, y
(11, 22)
>>> p.x + p.y                       # fields also accessible by name
33
>>> d = p._asdict()                 # convert to a dictionary
>>> d['x']
11
>>> Point(**d)                      # convert from a dictionary
Point(x=11, y=22)
>>> p._replace(x=100)               # _replace() is like str.replace() but targets named fields
Point(x=100, y=22)

�,� �_z*Type names and field names must be stringsz6Type names and field names must be valid identifiers: z0Type names and field names cannot be a keyword: z-Field names cannot start with an underscore: z"Encountered duplicate field name: z(Got more default values than field names�, rur�c3�*# �UH	oS3v� M g7f)z=%rNr")�.0�names  r�	<genexpr>�namedtuple.<locals>.<genexpr>�s���D����s�|��s�r��namedtuple_)�
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Q'�0Q�Q#�Q'�"Q#�#Q'c�J�URnUHnU"US5S-X'M g)z!Tally elements from the iterable.rruN)r)�mappingr��mapping_get�elems    r�_count_elementsr%s(���+�+�K���#�D�!�,�q�0��
�r))r%c�^�\rSrSrSrS!U4SjjrSrSrS!SjrSr	\
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jrSrSrSrSrSrSrSrSrSrSrSrSrSrSrSrSr Sr!Sr"S r#U=r$$)"ri$aDict subclass for counting hashable items.  Sometimes called a bag
or multiset.  Elements are stored as dictionary keys and their counts
are stored as dictionary values.

>>> c = Counter('abcdeabcdabcaba')  # count elements from a string

>>> c.most_common(3)                # three most common elements
[('a', 5), ('b', 4), ('c', 3)]
>>> sorted(c)                       # list all unique elements
['a', 'b', 'c', 'd', 'e']
>>> ''.join(sorted(c.elements()))   # list elements with repetitions
'aaaaabbbbcccdde'
>>> sum(c.values())                 # total of all counts
15

>>> c['a']                          # count of letter 'a'
5
>>> for elem in 'shazam':           # update counts from an iterable
...     c[elem] += 1                # by adding 1 to each element's count
>>> c['a']                          # now there are seven 'a'
7
>>> del c['b']                      # remove all 'b'
>>> c['b']                          # now there are zero 'b'
0

>>> d = Counter('simsalabim')       # make another counter
>>> c.update(d)                     # add in the second counter
>>> c['a']                          # now there are nine 'a'
9

>>> c.clear()                       # empty the counter
>>> c
Counter()

Note:  If a count is set to zero or reduced to zero, it will remain
in the counter until the entry is deleted or the counter is cleared:

>>> c = Counter('aaabbc')
>>> c['b'] -= 2                     # reduce the count of 'b' by two
>>> c.most_common()                 # 'b' is still in, but its count is zero
[('a', 3), ('c', 1), ('b', 0)]

c�H>�[TU]5 UR"U40UD6 g)a�Create a new, empty Counter object.  And if given, count elements
from an input iterable.  Or, initialize the count from another mapping
of elements to their counts.

>>> c = Counter()                           # a new, empty counter
>>> c = Counter('gallahad')                 # a new counter from an iterable
>>> c = Counter({'a': 4, 'b': 2})           # a new counter from a mapping
>>> c = Counter(a=4, b=2)                   # a new counter from keyword args

N)�superrNr�)rr�rHr�s   �rrN�Counter.__init__Ws!���	�������H�%��%r)c��g)z1The count of elements not in the Counter is zero.rr"r.s  r�__missing__�Counter.__missing__es��r)c�4�[UR55$)zSum of the counts)�sumr�rs r�total�
Counter.totaljs���4�;�;�=�!�!r)c��Uc"[UR5[S5SS9$SSKnUR	XR5[S5S9$)z�List the n most common elements and their counts from the most
common to the least.  If n is None, then list all element counts.

>>> Counter('abracadabra').most_common(3)
[('a', 5), ('b', 2), ('r', 2)]

NruT)r/�reverser)r/)�sortedr�r��heapq�nlargest)rr|r4s   r�most_common�Counter.most_commonnsD��
�9��$�*�*�,�K��N�D�I�I�	��~�~�a����;�q�>�~�B�Br)c�f�[R"[[UR	555$)a�Iterator over elements repeating each as many times as its count.

>>> c = Counter('ABCABC')
>>> sorted(c.elements())
['A', 'A', 'B', 'B', 'C', 'C']

Knuth's example for prime factors of 1836:  2**2 * 3**3 * 17**1

>>> import math
>>> prime_factors = Counter({2: 2, 3: 3, 17: 1})
>>> math.prod(prime_factors.elements())
1836

Note, if an element's count has been set to zero or is a negative
number, elements() will ignore it.

)�_chain�
from_iterable�_starmap�_repeatr�rs r�elements�Counter.elements~s"��&�#�#�H�W�d�j�j�l�$C�D�Dr)c��[S5e)Nz@Counter.fromkeys() is undefined.  Use Counter(iterable) instead.)�NotImplementedError)rFr��vs   rr��Counter.fromkeys�s��"�N�P�	Pr)c�&>�Ubt[U[R5(aJU(a3URnUR	5HupEXS"US5-X'M O[
TU]U5 O[X5 U(aUR
U5 gg)a�Like dict.update() but add counts instead of replacing them.

Source can be an iterable, a dictionary, or another Counter instance.

>>> c = Counter('which')
>>> c.update('witch')           # add elements from another iterable
>>> d = Counter('watch')
>>> c.update(d)                 # add elements from another counter
>>> c['h']                      # four 'h' in which, witch, and watch
4

Nr)r�r��Mappingrr�r(r�r%)rr�rH�self_getr$�countr�s      �rr��Counter.update�s{���(���(�$4�$<�$<�=�=��#�x�x�H�'/�~�~�'7���%*�X�d�A�->�%>��
�(8��G�N�8�,���/���K�K���r)c��UbjURn[U[R5(a(UR	5HupEU"US5U-
X'M OUHnU"US5S-
X'M U(aURU5 gg)a_Like dict.update() but subtracts counts instead of replacing them.
Counts can be reduced below zero.  Both the inputs and outputs are
allowed to contain zero and negative counts.

Source can be an iterable, a dictionary, or another Counter instance.

>>> c = Counter('which')
>>> c.subtract('witch')             # subtract elements from another iterable
>>> c.subtract(Counter('watch'))    # subtract elements from another counter
>>> c['h']                          # 2 in which, minus 1 in witch, minus 1 in watch
0
>>> c['w']                          # 1 in which, minus 1 in witch, minus 1 in watch
-1

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