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The relativedelta type is based on the specification of the excellent
work done by M.-A. Lemburg in his
`mx.DateTime <http://www.egenix.com/files/python/mxDateTime.html>`_ extension.
However, notice that this type does *NOT* implement the same algorithm as
his work. Do *NOT* expect it to behave like mx.DateTime's counterpart.
There are two different ways to build a relativedelta instance. The
first one is passing it two date/datetime classes::
relativedelta(datetime1, datetime2)
The second one is passing it any number of the following keyword arguments::
relativedelta(arg1=x,arg2=y,arg3=z...)
year, month, day, hour, minute, second, microsecond:
Absolute information (argument is singular); adding or subtracting a
relativedelta with absolute information does not perform an aritmetic
operation, but rather REPLACES the corresponding value in the
original datetime with the value(s) in relativedelta.
years, months, weeks, days, hours, minutes, seconds, microseconds:
Relative information, may be negative (argument is plural); adding
or subtracting a relativedelta with relative information performs
the corresponding aritmetic operation on the original datetime value
with the information in the relativedelta.
weekday:
One of the weekday instances (MO, TU, etc). These instances may
receive a parameter N, specifying the Nth weekday, which could
be positive or negative (like MO(+1) or MO(-2). Not specifying
it is the same as specifying +1. You can also use an integer,
where 0=MO.
leapdays:
Will add given days to the date found, if year is a leap
year, and the date found is post 28 of february.
yearday, nlyearday:
Set the yearday or the non-leap year day (jump leap days).
These are converted to day/month/leapdays information.
Here is the behavior of operations with relativedelta:
1. Calculate the absolute year, using the 'year' argument, or the
original datetime year, if the argument is not present.
2. Add the relative 'years' argument to the absolute year.
3. Do steps 1 and 2 for month/months.
4. Calculate the absolute day, using the 'day' argument, or the
original datetime day, if the argument is not present. Then,
subtract from the day until it fits in the year and month
found after their operations.
5. Add the relative 'days' argument to the absolute day. Notice
that the 'weeks' argument is multiplied by 7 and added to
'days'.
6. Do steps 1 and 2 for hour/hours, minute/minutes, second/seconds,
microsecond/microseconds.
7. If the 'weekday' argument is present, calculate the weekday,
with the given (wday, nth) tuple. wday is the index of the
weekday (0-6, 0=Mon), and nth is the number of weeks to add
forward or backward, depending on its signal. Notice that if
the calculated date is already Monday, for example, using
(0, 1) or (0, -1) won't change the day.
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Return a version of this object represented entirely using integer
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>>> relativedelta(days=1.5, hours=2).normalized()
relativedelta(days=1, hours=14)
:return:
Returns a :class:`dateutil.relativedelta.relativedelta` object.
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